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Indicate the concentration of each ion present in the solution formed by mixing 42.0 mL of 0.170 M NaOH with 37.6 mL of 0.400 M NaOH,
Answer: nNaOH = nNa+ = nOH- = 0.022mol.
We can do this by calculating the volume and molarity of the final solution. Once we have that we can easily determine the amount of moles of each of the ions. With NaOH, the amount of NaOH will be the same as the amount of Na+ and OH- (ratio 1:1). Therefore:
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