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8.3.9 Owls, Part 2 CodeHS Answers

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The most common answer is:

def owl_count():
count = 0
report = []
text = input(“Enter a sentence: “)
text = text.lower()
for index, word in enumerate(text.split()):
f word.find(“owl”) > -1:
count += 1
report += [index,]
print(“There were ” + str(count) + “”” words that contained “owl”.”””)
print(“They occurred at indices: ” + str(report))
owl_count()

The owl_count function is structured to count the occurrences of the word “owl” in a user-entered sentence and report the indices (word positions) where “owl” appears.

There’s a small typo in the code, and it can be slightly optimized for readability.

Additionally, let’s correct the quotation marks to ensure compatibility with Python syntax:

def owl_count():
    count = 0
    report = []
    text = input("Enter a sentence: ")
    text = text.lower()
    for index, word in enumerate(text.split()):
        if "owl" in word:  # Simplified condition to check for "owl" in each word
            count += 1
            report.append(index)  # Use append to add the index to the report list
    
    print("There were " + str(count) + " words that contained 'owl'.")
    print("They occurred at indices: " + str(report))

owl_count()

This version does the following:

  • Prompts the user to enter a sentence and converts it to lowercase to ensure the search is case-insensitive.
  • Splits the sentence into words and iterates over them with their indices using enumerate.
  • Checks if “owl” is a substring of each word. If it is, increments the count and adds the word’s index to the report list.
  • After checking all words, prints the total count of words containing “owl” and the indices of those words within the input sentence.

Note that the indices reported are based on the word positions in the list generated by splitting the input sentence, starting from 0.

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