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7.6.8 What’s in a Name? CodeHS Answers

The most common answer is:

fill in the arguments and function body
name = “Thelas”
letter= “e”
def name_contains(name, letter):
if name.find(letter) != -1:
return True
return False
print (name_contains(name, letter))

This function name_contains is almost set up correctly to check if letter is in name. However, we can streamline the function by directly returning the result of the comparison without the need for an if-else statement.

Here’s the revised version of the code:

name = "Thelas"
letter = "e"

def name_contains(name, letter):
    return name.find(letter) != -1

print(name_contains(name, letter))

This version of the function checks whether letter is in name by using the .find() method, which returns the index of letter in name if found, or -1 if it’s not found. The comparison name.find(letter) != -1 directly evaluates to True if the letter is found and False otherwise. This boolean value is then returned by the function.

The print statement calls name_contains with name and letter as arguments and prints the result, which will be True if letter is found in name, or False if it is not.

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