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6.5.6 Temperature Converter Part 2 CodeHS Answers

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The most common answer is:

def convert_C_to_F(c):
f = ((1.8*c) + 32)
return float(f)
Now write your function for converting Fahrenheit to Celcius.
def convert_F_to_C(f):
c = ((f-32) / 1.8)
return float(c)
try:
x = float(input())
except ValueError:
print(“An error has occured”)
try:
y = float(input())
except ValueError:
print(“An error has occured”)
print(convert_C_to_F(x))
Change 100C to F:
print(convert_C_to_F(y))

To make your Temperature Converter function correctly and handle user input more clearly, including converting Celsius to Fahrenheit and vice versa, let’s organize and correct your code.

Additionally, it seems there’s some confusion in the user input part, as it doesn’t specify what the input is for.

Let’s also address that by adding prompts to the input function calls:

# Converts Celsius to Fahrenheit
def convert_C_to_F(c):
    f = ((1.8 * c) + 32)
    return float(f)

# Converts Fahrenheit to Celsius
def convert_F_to_C(f):
    c = ((f - 32) / 1.8)
    return float(c)

# Attempt to get Celsius input from the user
try:
    celsius = float(input("Enter a temperature in Celsius: "))
    print(f"{celsius}C is {convert_C_to_F(celsius)}F")
except ValueError:
    print("An error has occurred")

# Attempt to get Fahrenheit input from the user
try:
    fahrenheit = float(input("Enter a temperature in Fahrenheit: "))
    print(f"{fahrenheit}F is {convert_F_to_C(fahrenheit)}C")
except ValueError:
    print("An error has occurred")

This corrected and enhanced code:

  • Clearly prompts the user for a temperature in Celsius, attempts to convert it to Fahrenheit, and prints the result.
  • Similarly, it prompts for a temperature in Fahrenheit, converts it to Celsius, and prints the outcome.
  • Uses try-except blocks to catch ValueError in case of non-numeric input, printing an error message if such an exception occurs.
  • Demonstrates the use of the functions convert_C_to_F and convert_F_to_C for temperature conversions.

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Quizzma Team

The Quizzma Team is a collective of experienced educators, subject matter experts, and content developers dedicated to providing accurate and high-quality educational resources. With a diverse range of expertise across various subjects, the team collaboratively reviews, creates, and publishes content to aid in learning and self-assessment.
Each piece of content undergoes a rigorous review process to ensure accuracy, relevance, and clarity. The Quizzma Team is committed to fostering a conducive learning environment for individuals and continually strives to provide reliable and valuable educational resources on a wide array of topics. Through collaborative effort and a shared passion for education, the Quizzma Team aims to contribute positively to the broader learning community.

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