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Describe the given region in polar coordinates

Describe the given region in polar coordinates.

Describe the given region in polar coordinates

1 Answer

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AnonymousJuly 9, 2024

To describe the given region in polar coordinates, we need to convert the boundaries of the region from Cartesian coordinates to polar coordinates.

The region is bounded by:

  1. The straight lines x=4x = 4 and y=6y = 6
  2. The curve of the quarter circle with radius 6

Converting boundaries to polar coordinates:

  1. Quarter circle with radius 6:
    • r=6r = 6
  2. Line x=4x = 4
    • In polar coordinates, x=rcosθ=4x = r \cos \theta = 4
    • Therefore, r=4cosθ=4secθr = \frac{4}{\cos \theta} = 4 \sec \theta
  3. Line y=6y = 6y=6:
    • In polar coordinates, y=rsinθ=6y = r \sin \theta = 6
    • Therefore, r=6sinθ=6cscθr = \frac{6}{\sin \theta} = 6 \csc \theta

Describing the region in polar coordinates:

The region is divided into two parts based on θ\thetaθ:

  • Lower portion:
    • 0θπ60 \leq \theta \leq \frac{\pi}{6}
    • 1r6secθ1 \leq r \leq 6 \sec \theta
  • Upper portion:
    • π6θπ2\frac{\pi}{6} \leq \theta \leq \frac{\pi}{2}
    • 1r6cscθ1 \leq r \leq 6 \csc \theta

So, the full description in polar coordinates is:

  • Lower portion:
    • 0θπ60 \leq \theta \leq \frac{\pi}{6}
    • 1r6secθ1 \leq r \leq 6 \sec \theta
  • Upper portion:
    • π6θπ2\frac{\pi}{6} \leq \theta \leq \frac{\pi}{2}
    • 1r6cscθ1 \leq r \leq 6 \csc \theta