1. Calculate the Volume of the Pond:

   The dimensions of the pond are:

   • Length: 50 m
   • Width: 15 m
   • Depth: 2 m

   The volume $VV$ of the pond is:

   $V=length\times width\times depthV\; =\; \backslash text\{length\}\; \backslash times\; \backslash text\{width\}\; \backslash times\; \backslash text\{depth\}$
   $V=50\hspace{0.17em}m\times 15\hspace{0.17em}m\times 2\hspace{0.17em}mV\; =\; 50\; \backslash ,\; \backslash text\{m\}\; \backslash times\; 15\; \backslash ,\; \backslash text\{m\}\; \backslash times\; 2\; \backslash ,\; \backslash text\{m\}$
   $V=1500\hspace{0.17em}{3}^{}V\; =\; 1500\; \backslash ,\; \backslash text\{m\}^3$
   

2. Convert Density to kg/m³:

   The given density of the waste is $85.3\hspace{0.17em}{3}^{}85.3\; \backslash ,\; \backslash text\{lbm/ft\}^3$85.3. We need to convert this to kg/m³.

   • 1 pound mass (lbm) is approximately 0.45359237 kilograms.
   • 1 cubic foot (ft³) is approximately 0.0283168 cubic meters.

   $3^{}=85.3\hspace{0.17em}{3}^{}\times 0.45359237\hspace{0.17em}kg/lbm÷0.0283168\hspace{0.17em}{3}^{}\mathrm{/}{3}^{}\backslash text\{Density\; in\; kg/m\}^3\; =\; 85.3\; \backslash ,\; \backslash text\{lbm/ft\}^3\; \backslash times\; 0.45359237\; \backslash ,\; \backslash text\{kg/lbm\}\; \backslash div\; 0.0283168\; \backslash ,\; \backslash text\{m\}^3/\backslash text\{ft\}^3$
   $3^{}=85.3\times 0.45359237÷0.0283168\backslash text\{Density\; in\; kg/m\}^3\; =\; 85.3\; \backslash times\; 0.45359237\; \backslash div\; 0.0283168$
   $3^{}\approx 1367.89\hspace{0.17em}{3}^{}\backslash text\{Density\; in\; kg/m\}^3\; \backslash approx\; 1367.89\; \backslash ,\; \backslash text\{kg/m\}^3$
   

3. Calculate the Mass of the Pond Contents:

   $Mass=Volume\times Density\backslash text\{Mass\}\; =\; \backslash text\{Volume\}\; \backslash times\; \backslash text\{Density\}$
   $Mass=1500\hspace{0.17em}{3}^{}\times 1367.89\hspace{0.17em}{3}^{}\backslash text\{Mass\}\; =\; 1500\; \backslash ,\; \backslash text\{m\}^3\; \backslash times\; 1367.89\; \backslash ,\; \backslash text\{kg/m\}^3$
   $Mass\approx 2051835\hspace{0.17em}kg\backslash text\{Mass\}\; \backslash approx\; 2051835\; \backslash ,\; \backslash text\{kg\}$
   

4. Convert Mass to $10^{4}10^4$104 kg:

   $Mass in 10^4\hspace{0.17em}kg=\frac{2051835\hspace{0.17em}kg}{10^4}\backslash text\{Mass\; in\; \}\; 10^4\; \backslash ,\; \backslash text\{kg\}\; =\; \backslash frac\{2051835\; \backslash ,\; \backslash text\{kg\}\}\{10^4\}$​ $Mass in 10^4\hspace{0.17em}kg\approx 205.18\backslash text\{Mass\; in\; \}\; 10^4\; \backslash ,\; \backslash text\{kg\}\; \backslash approx\; 205.18$
   

Answer:

The weight of the pond contents is approximately $205.18\times 10^{4}205.18\; \backslash times\; 10^4$205.18×104 kilograms.