Which is the equation of a circle with a radius of 3 and a center at (0, 0)?
A. x² + y² = 3
B. x² + y² = 6
C. x² + y² = 9
D. (x – 3)² + (y – 3)² = 0
E. (x + 3)² + (y + 3)² = 0
Which is the equation of a circle with a radius of 3 and a center at (0, 0)
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The equation of a circle is given by the formula ((x – h)^2 + (y – k)^2 = r^2), where ((h, k)) is the center of the circle and (r) is the radius.
In this case:
– The center is at ((0, 0)), so (h = 0) and (k = 0).
– The radius is (3), so (r = 3).
Substituting these values into the equation gives us:
((x – 0)^2 + (y – 0)^2 = 3^2)
This simplifies to:
(x^2 + y^2 = 9)
Therefore, the correct answer is:
C. x² + y² = 9
This equation represents a circle centered at the origin with a radius of 3. Keep up the great work! If you need more help, check the extended services page.