Which is the equation of a circle with a radius of 3 and a center at (0, 0)

The equation of a circle is given by the formula ((x – h)^2 + (y – k)^2 = r^2), where ((h, k)) is the center of the circle and (r) is the radius.

In this case:

– The center is at ((0, 0)), so (h = 0) and (k = 0).

– The radius is (3), so (r = 3).

Substituting these values into the equation gives us:

((x – 0)^2 + (y – 0)^2 = 3^2)

This simplifies to:

(x^2 + y^2 = 9)

Therefore, the correct answer is:

C. x² + y² = 9

This equation represents a circle centered at the origin with a radius of 3. Keep up the great work! If you need more help, check the extended services page.