Which is a value of x, when 3x² + 4 = 40?
A x = 2√3
B x = 2√6
C x = 2√11
D x = 3√2
E x = 6√2
Value of x in the equation 3x² + 4 = 40
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Which is a value of x, when 3x² + 4 = 40?
A x = 2√3
B x = 2√6
C x = 2√11
D x = 3√2
E x = 6√2
To solve the equation 3x² + 4 = 40, follow these steps:
1. Subtract 4 from both sides:
[
3x² = 40 – 4
]
[
3x² = 36
]
2. Divide both sides by 3:
[
x² = frac{36}{3}
]
[
x² = 12
]
3. Take the square root of both sides:
[
x = pm sqrt{12}
]
Since ( sqrt{12} = sqrt{4 times 3} = 2sqrt{3} ), we have:
[
x = pm 2sqrt{3}
]
The correct option that matches this solution is A x = 2√3.
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