Value of x in the equation 3x² + 4 = 40

To solve the equation 3x² + 4 = 40, follow these steps:

1. Subtract 4 from both sides:

[

3x² = 40 – 4

]

[

3x² = 36

]

2. Divide both sides by 3:

[

x² = frac{36}{3}

]

[

x² = 12

]

3. Take the square root of both sides:

[

x = pm sqrt{12}

]

Since ( sqrt{12} = sqrt{4 times 3} = 2sqrt{3} ), we have:

[

x = pm 2sqrt{3}

]

The correct option that matches this solution is A x = 2√3.

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