If a heterozygous tall pea plant, which is a dominant trait, is crossed with a short pea plant, what percent of the offspring will be heterozygous?
0%
25%
50%
100%
Part B.
What percent of the offspring will be short?
0%
25%
50%
100%
If a heterozygous tall pea plant, which is a dominant trait, is crossed with a short pea plant, what percent of the offspring will be heterozygous? What percent of the offspring will be short?
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To solve this problem, let’s begin with the genetic information provided:
– The tall trait (T) is dominant.
– The short trait (t) is recessive.
– A heterozygous tall pea plant has the genotype Tt.
– The short pea plant has the genotype tt.
Part A: Heterozygous Offspring
When we cross Tt (heterozygous tall) with tt (short), we can set up a punnett square:
T | t
-------------------
t | Tt | tt
-------------------
t | Tt | tt
From the punnett square, we see the possible genotypes of the offspring:
– 50% Tt (heterozygous tall)
– 50% tt (homozygous short)
So, 50% of the offspring will be heterozygous (Tt).
Part B: Short Offspring
From the same punnett square, we find:
– 50% of the offspring are tt (short).
So, 50% of the offspring will be short.
In summary:
– For Part A: 50%
– For Part B: 50%
Feel free to ask if you have more questions or need further assistance!