If a heterozygous tall pea plant, which is a dominant trait, is crossed with a short pea plant, what percent of the offspring will be heterozygous? What percent of the offspring will be short?

To solve this problem, let’s begin with the genetic information provided:

– The tall trait (T) is dominant.

– The short trait (t) is recessive.

– A heterozygous tall pea plant has the genotype Tt.

– The short pea plant has the genotype tt.

Part A: Heterozygous Offspring

When we cross Tt (heterozygous tall) with tt (short), we can set up a punnett square:

T | t

-------------------

t | Tt | tt

-------------------

t | Tt | tt

From the punnett square, we see the possible genotypes of the offspring:

– 50% Tt (heterozygous tall)

– 50% tt (homozygous short)

So, 50% of the offspring will be heterozygous (Tt).

Part B: Short Offspring

From the same punnett square, we find:

– 50% of the offspring are tt (short).

So, 50% of the offspring will be short.

In summary:

– For Part A: 50%

– For Part B: 50%

Feel free to ask if you have more questions or need further assistance!