Which equation can be used to solve for the number of classes, c, for which Class A and Class B cost the same?
40c = 25 + 60c
40c + 60 = 25c
40c = 25c + 60
Which equation can be used to solve for the number of classes, c, for which Class A and Class B cost the same?
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To find the equation that can be used to solve for the number of classes, ( c ), where the costs of Class A and Class B are equal, we need to analyze the provided equations:
1. 40c = 25 + 60c
This equation states that the cost of Class A (40c) is equal to the cost of Class B (60c) plus $25. This is a valid equation to use.
2. 40c + 60 = 25c
This equation does not represent the scenario of equal costs correctly. It implies that the total cost of Class A plus some value (60) equals the cost of Class B, which is not what we want.
3. 40c = 25c + 60
This equation suggests that the cost of Class A (40c) is equal to the cost of Class B (25c) plus $60. This also accurately describes a cost equality scenario.
Thus, the two correct equations for solving when Class A and Class B cost the same are the first (40c = 25 + 60c) and the third (40c = 25c + 60).
For your question, I recommend using 40c = 25 + 60c or 40c = 25c + 60 to solve for ( c ). Both represent valid scenarios for cost equality.
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