sum ← 0
REPEAT x TIMES
{
sum ← sum + 1
}
REPEAT y TIMES
{
sum ← sum + 1
}
sum ← 0
REPEAT y TIMES
{
REPEAT x TIMES
{
sum ← sum + 1
}
}
sum ← 0
z ← x * y
REPEAT z TIMES
{
sum ← sum + 1
}
What is the final value of sum after executing the given code snippets?
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To understand the code snippets provided, we can break them down by analyzing each segment to determine the value of `sum` after the execution of each block.
1. First Segment:
sum ← 0
REPEAT x TIMES
{
sum ← sum + 1
}
REPEAT y TIMES
{
sum ← sum + 1
}
In this segment, `sum` is initialized to 0. The first loop runs `x` times, incrementing `sum` by 1 for each iteration, resulting in `sum` being `x`. The second loop runs `y` times, further incrementing `sum` by 1 for each iteration, resulting in `sum` being `x + y`.
2. Second Segment:
“`plaintext
sum ← 0
REPEAT y TIMES
{
REPEAT x TIMES
{
sum ← sum + 1
}
}
Here, `sum` is again reset to 0. The outer loop runs `y` times, and for each iteration of the outer loop, the inner loop runs `x` times, thus incrementing `sum` by `x` for each iteration of the outer loop. The total increment would be `y * x`, which equals `x * y`.
3. Third Segment: