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Using the Pythagorean Theorem to Find the Distance Between Two Points

Two points are located at (−9, −8) and (−6, −4).

Complete the equations below to show how you can use the Pythagorean theorem to find the distance between these two points.

Solve a² + b² = c² for c.

c =

Use coordinates to write an expression for the distance between the two points.

c = √( ( )² + ( )² )




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1 Answer

  1. To find the distance between the points ((-9, -8)) and ((-6, -4)), we can use the Pythagorean theorem.

    1. First, we identify the horizontal and vertical distances between the points:

    – The horizontal distance (change in x) is: (-6 – (-9) = -6 + 9 = 3)

    – The vertical distance (change in y) is: (-4 – (-8) = -4 + 8 = 4)

    2. Now, we can set up the Pythagorean theorem:

    [

    a^2 + b^2 = c^2

    ]

    Here, (a = 3) (horizontal distance) and (b = 4) (vertical distance).

    3. Plugging in the values:

    [

    c^2 = 3^2 + 4^2

    ]

    [

    c^2 = 9 + 16 = 25

    ]

    [

    c = sqrt{25} = 5

    ]

    So, the equation to express the distance between the points is:

    c = √( (3)² + (4)² )

    The final answer for the distance (c) is 5. This demonstrates how we can use the Pythagorean theorem to calculate the distance between two points in a

  2. To find the distance between the points ((-9, -8)) and ((-6, -4)), we can treat the difference in their coordinates as the two legs of a right triangle.

    1. Find the lengths of the legs (a and b):

    – The change in the x-coordinates (a) is:

    [

    -6 – (-9) = -6 + 9 = 3

    ]

    – The change in the y-coordinates (b) is:

    [

    -4 – (-8) = -4 + 8 = 4

    ]

    2. Apply the Pythagorean theorem:

    [

    a^2 + b^2 = c^2

    ]

    Plugging in the values:

    [

    3^2 + 4^2 = c^2

    ]

    Simplifying it:

    [

    9 + 16 = c^2

    ]

    [

    25 = c^2

    ]

    Taking the square root of both sides:

    [

    c = 5

    ]

    3. Write the distance formula using coordinates:

    [

    c = sqrt{(x_2 – x_1)^2 + (y_2 – y_1)^2}

    ]

    Substituting the

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