The graph of h is the graph of g(x) = (x – 2)² + 6 translated 5 units left and 3 units down.
a. Describe the graph of h as a translation of the graph of f(x) = x².
b. Write the function h in vertex form.
a. The graph of h is the graph of f(x) = x² translated ___ unit(s) ___ and ___ unit(s) ___.
(Type whole numbers.)
To solve the problem, let’s break it down step by step.
### a. Describe the graph of h as a translation of the graph of f(x) = x².
1. Starting Function: The graph of f(x) = x² has its vertex at the origin (0, 0).
2. Translation: The function g(x) = (x – 2)² + 6 has its vertex at (2, 6). To get from f(x) to g(x), we shift the graph 2 units to the right and 6 units up.
3. Final Translation to h: The graph of h is then translated 5 units left and 3 units down from g(x):
– Moving 5 units left from (2, 6) brings us to (-3, 6).
– Moving 3 units down from (−3, 6) gives us the new vertex at (−3, 3).
Thus, from f(x) to h:
– Translation: The graph of h is the graph of f(x) = x² translated 3 units down and 5 units left.
### b. Write the function h in vertex form.
1. Vertex from Translation: The new vertex for h is (-3, 3).
2. Vertex Form: The vertex form of a quadratic function is h(x) = a(x – h)² + k, where (h, k