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Find the slope of the table and the equation. Do they have the same slopes? y = 4x – 6 Slope of table == Slope of equation == Yes, the slopes are the same. No, the slopes are not the same. Let y be the seconds to takes to run a mile and x be the number of days spent practicing. A linear model was created with the following equation: y = -2x + 686 What is the predicted seconds to takes to run a mile when a student spends 6 days practicing?

Find the slope of the table and the equation. Do they have the same slopes?
y = 4x – 6
Slope of table ==
Slope of equation ==
Yes, the slopes are the same.
No, the slopes are not the same.

Let y be the seconds to takes to run a mile and x be the number of days spent practicing. A linear model was created with the following equation: y = -2x + 686
What is the predicted seconds to takes to run a mile when a student spends 6 days practicing?




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1 Answer

  1. To solve for the predicted seconds to run a mile when a student spends 6 days practicing using the equation ( y = -2x + 686 ), follow these steps:

    1. Substitute ( x = 6 ) into the equation:

    [

    y = -2(6) + 686

    ]

    2. Calculate ( -2(6) ):

    [

    -2(6) = -12

    ]

    3. Now add ( -12 ) to ( 686 ):

    [

    y = -12 + 686

    ]

    [

    y = 674

    ]

    So, the predicted seconds to run a mile when a student spends 6 days practicing is 674 seconds.

    This means that after practicing for 6 days, the student’s performance would lead to an estimated time of 674 seconds to complete a mile. If you have any further questions or need more clarification, feel free to ask or check the extended services page for more help!

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