Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Use the Pythagorean Theorem to find the distance between points P and Q to the nearest tenth.
Label the length, in units, of each leg of the right triangle.
c² = _____² + _____²
c² = _____ + _____
c = √_____
The distance between point P and point Q is _____ units.
To find the distance between points P and Q using the Pythagorean Theorem, we first need to identify the coordinates of points P and Q. Let’s assume point P has coordinates ((x_1, y_1)) and point Q has coordinates ((x_2, y_2)).
Step 1: Calculate the lengths of the legs of the triangle.
The length of one leg (let’s call it (a)) is the difference in the x-coordinates:
(a = |x_2 – x_1|)
The length of the other leg (let’s call it (b)) is the difference in the y-coordinates:
(b = |y_2 – y_1|)
Step 2: Apply the Pythagorean Theorem.
The Pythagorean Theorem states:
[c^2 = a^2 + b^2]
Step 3: Substitute the values into the formula.
Thus, you would write:
[
c^2 = (|x_2 – x_1|)^2 + (|y_2 – y_1|)^2
]
Step 4: Solve for (c).
To find (c), which is the distance between points P and Q:
[
c = sqrt{(|x_2 – x_1|)^2 + (|y_2 – y_1|)^2}
]
Step