Write the equation in standard form.
2y + 3 = -1/3(x – 2)
Write the equation in standard form. 2y + 3 = -1/3(x – 2)
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Write the equation in standard form.
2y + 3 = -1/3(x – 2)
To write the equation (2y + 3 = -frac{1}{3}(x – 2)) in standard form, we will follow these steps:
1. Distribute the (-frac{1}{3}) on the right side:
[
2y + 3 = -frac{1}{3}x + frac{2}{3}
]
2. Subtract 3 from both sides to isolate the (y) term:
[
2y = -frac{1}{3}x + frac{2}{3} – 3
]
Convert (3) to a fraction with a denominator of 3:
[
3 = frac{9}{3}
]
So, we have:
[
2y = -frac{1}{3}x + frac{2}{3} – frac{9}{3}
]
This simplifies to:
[
2y = -frac{1}{3}x – frac{7}{3}
]
3. Multiply the whole equation by 3 to eliminate the fractions:
[
3(2y) = 3left(-frac{1}{3}xright) – 3left(-frac{7