Write a function called is_even that takes one parameter and returns a boolean value

Question

Write a function called is_even that takes one parameter and returns a boolean value. It should return True if the argument is even; it should return False otherwise. The is_even function should not print anything out or return a number. It should only take in a number and return a boolean. Note: Be sure to include comments for all functions that you use or create. For example, if you made a call like: python Копировать код is_even_number = is_even( 4 ) is_even_number should have the value True . Once you’ve written this function, write a program that asks the user for integers and prints whether the number they entered is even or odd using your is_even function. You should let the user keep entering numbers until they enter the SENTINEL value. Example: Enter a number: 5 Odd Enter a number: 42 Even Enter a number: -6 Even Enter a number: 0 Done!

Quizzma Team · Answer

Here’s how you can create the `is_even` function and a program to interact with the user:

def is_even(number):

"""Check if the number is even.

Args:

number (int): The number to check.

Returns:

bool: True if the number is even, False otherwise.

"""

return number % 2 == 0 # Returns True if the number is divisible by 2

# Sentinel value to stop the program

SENTINEL = 0

while True:

user_input = int(input("Enter a number: ")) # Ask the user for input

if user_input == SENTINEL: # Check if the input is the sentinel value

print("Done!")

break # Exit the loop

# Use the is_even function to check the number

if is_even(user_input):

print("Even")

else:

print("Odd")

### Explanation:

– Function Definition: The `is_even` function takes one parameter (an integer) and returns `True` if the number is even (i.e., divisible by 2 without a remainder) and `False` otherwise.

– User Input Loop: The program uses a `while` loop to continuously prompt the user for input until the sentinel value (0) is entered. It checks if the input number is even or odd using the `is_even` function and prints the corresponding

Quizzma Team · Answer

Here’s how you can write the `is_even` function and the program to check if a number is even or odd based on user input.

def is_even(number):

"""

Check if a number is even.

Parameters:

number (int): The number to check.

Returns:

bool: True if the number is even, False otherwise.

"""

return number % 2 == 0 # Returns True if number is even, False if odd

# Sentinel value to end the input loop

SENTINEL = 'done'

# Start a loop to get user input

while True:

user_input = input("Enter a number (or type 'done' to exit): ")

if user_input.lower() == SENTINEL:

print("Done!") # Print a message when user enters the sentinel value

break # Exit the loop

try:

number = int(user_input) # Convert input to an integer

if is_even(number): # Check if the number is even

print("Even")

else:

print("Odd") # If it's not even, it's odd

except ValueError:

print("Please enter a valid integer.") # Handle invalid input

### Explanation:
1. is_even Function: This function takes one parameter (a number) and uses the modulo operator `%` to check if the number is even

Anonymous · Answer

# Function to check if a number is even
def is_even(number):
“””
This function takes an integer as input and returns True if the number is even,
otherwise it returns False.
“””
return number % 2 == 0

# Main program
print(“Enter numbers to check if they are even or odd. Enter 0 to stop.”)
while True:
# Input from the user
num = int(input(“Enter a number: “))

# Sentinel value to break the loop
if num == 0:
print(“Done!”)
break

# Use is_even function to check and print result
if is_even(num):
print(“Even”)
else:
print(“Odd”)

Write a function called is_even that takes one parameter and returns a boolean value

3 Answers