Solve the system by substitution

To solve the system of equations by substitution, we follow these steps:

1. We have the equations:

[

7x – 3y = 8 quad (1)

]

[

y = 3x quad (2)

]

2. Substitute equation (2) into equation (1):

Replace ( y ) in (1) with ( 3x ):

[

7x – 3(3x) = 8

]

Simplifying gives:

[

7x – 9x = 8

]

[

-2x = 8

]

[

x = -4

]

3. Now, substitute ( x = -4 ) back into equation (2) to find ( y ):

[

y = 3(-4) = -12

]

4. So, the solution of the system is ( (x, y) = (-4, -12) ).

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