I am a three digit number. My second digit is four times more than my third digit. My first digit is seven less than my second digit. What am I?

Let’s break down the problem step-by-step.

We have a three-digit number represented as ‘ABC’, where:

– A is the first digit,

– B is the second digit,

– C is the third digit.

From the clues provided:
1. B is four times more than C. This can be expressed as:

( B = 4C )

2. A is seven less than B, which can be written as:

( A = B – 7 )

Now, we need to check each option:

1) 128:

– A = 1, B = 2, C = 8

– B = 4C → ( 2 neq 4 times 8 ) (False)

2) 236:

– A = 2, B = 3, C = 6

– B = 4C → ( 3 neq 4 times 6 ) (False)

3) 324:

– A = 3, B = 2, C = 4

– B = 4C → ( 2 neq 4 times 4 ) (False)

4) 472:

– A = 4, B = 7, C = 2

– B = 4C → ( 7 = 4 times 2 ) (True)