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Examine the table for the densities of various substances above. If a student has an unknown substance with a mass of 27.02g and a volume of 1.4mL. A milliliter is equivalent to a cubic centimeter. Which statements can be supported by the information given here? Select both that apply.

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Examine the table for the densities of various substances above. If a student has an unknown substance with a mass of 27.02g and a volume of 1.4mL. A milliliter is equivalent to a cubic centimeter. Which statements can be supported by the information given here? Select both that apply.
A The substance will sink in water.
B The substance will float in water.
C The substance is likely nickel.
D The substance is likely lead.
E The substance is likely gold.




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  1. To determine which statements can be supported by the information given, we first need to calculate the density of the unknown substance.

    Density is calculated using the formula:

    [ text{Density} = frac{text{Mass}}{text{Volume}} ]

    For the unknown substance:

    – Mass = 27.02 g

    – Volume = 1.4 mL (which is equivalent to 1.4 cm³)

    Now, calculating the density:

    [ text{Density} = frac{27.02 , text{g}}{1.4 , text{cm}^3} approx 19.3 , text{g/cm}^3 ]

    Now, let’s compare this density to common substances:

    – Water has a density of about 1 g/cm³. Since 19.3 g/cm³ is much greater than 1 g/cm³, the substance will sink in water (so Statement A is true).

    – Nickel has a density of about 8.9 g/cm³, lead is about 11.3 g/cm³, and gold is about 19.3 g/cm³. Given that the calculated density is approximately equal to the density of gold, we can conclude that it is likely gold (so Statement E is true).

    Therefore, the correct statements supported by the information given are:

    A. The substance will sink in water.

    **E. The substance is likely gold.

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