Examine the table for the densities of various substances above. If a student has an unknown substance with a mass of 27.02g and a volume of 1.4mL. A milliliter is equivalent to a cubic centimeter. Which statements can be supported by the information given here? Select both that apply.

To determine which statements can be supported by the information given, we first need to calculate the density of the unknown substance.

Density is calculated using the formula:

[ text{Density} = frac{text{Mass}}{text{Volume}} ]

For the unknown substance:

– Mass = 27.02 g

– Volume = 1.4 mL (which is equivalent to 1.4 cm³)

Now, calculating the density:

[ text{Density} = frac{27.02 , text{g}}{1.4 , text{cm}^3} approx 19.3 , text{g/cm}^3 ]

Now, let’s compare this density to common substances:

– Water has a density of about 1 g/cm³. Since 19.3 g/cm³ is much greater than 1 g/cm³, the substance will sink in water (so Statement A is true).

– Nickel has a density of about 8.9 g/cm³, lead is about 11.3 g/cm³, and gold is about 19.3 g/cm³. Given that the calculated density is approximately equal to the density of gold, we can conclude that it is likely gold (so Statement E is true).

Therefore, the correct statements supported by the information given are:

A. The substance will sink in water.

**E. The substance is likely gold.