Complete the Punnett Square. Find probability of each phenotype in the offspring.
Probability of no horns
Probability of having horns
Complete the Punnett Square. Find probability of each phenotype in the offspring. Probability of no horns Probability of having horns
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To complete the Punnett Square and find the probabilities of each phenotype in the offspring, we first need to know the genotypes of the parents. For instance, if we assume “H” represents the dominant allele for having horns and “h” represents the recessive allele for no horns, let’s say one parent is homozygous dominant (HH) and the other is homozygous recessive (hh).
Here’s how the Punnett Square would look:
H H
-----------------
h | Hh | Hh |
-----------------
h | Hh | Hh |
-----------------
From this Punnett Square, all offspring (100%) would have the genotype Hh, which means they all will have horns since horns are the dominant trait.
Probabilities:
– Probability of no horns (hh) = 0%
– Probability of having horns (Hh) = 100%
If the parent genotypes were different, please provide those, and I can help adjust the explanation accordingly!