An isosceles triangle has an angle that measures 80°. What measures are possible for the other two angles?

In an isosceles triangle, two angles are equal, and the sum of all angles in a triangle is always 180°.

Given that one angle measures 80°, the remaining two angles can be denoted as ( x ) (since they are the ones that are equal). We can set up the equation:

[ 80° + x + x = 180° ]

This simplifies to:

[ 80° + 2x = 180° ]

Subtracting 80° from both sides gives:

[ 2x = 100° ]

Dividing by 2 results in:

[ x = 50° ]

Thus, the two other angles must each measure 50°.

From the options given, the possible measures for the other two angles are:

– 50°

The other options (40°, 20°, and another 80°) do not satisfy the conditions for the angles in this isosceles triangle.

So, the correct answer is 50°. If you have further questions or need additional assistance, feel free to ask!