A warehouse holds 147,016 shoeboxes. Each aisle holds the same number of boxes. How many aisles could there be? Select all the possible numbers. 2 10 4 8.

To determine how many aisles could hold 147,016 shoeboxes with each aisle holding the same number, we need to find all the divisors of 147,016.

First, let’s factor 147,016:
1. Divide by 2 (since it’s even) until we can’t anymore:

– 147,016 ÷ 2 = 73,508

– 73,508 ÷ 2 = 36,754

– 36,754 ÷ 2 = 18,377 (now it’s odd)

Since 18,377 is not easily factorable by small primes, let’s check the divisibility of some of the options:

– 2: Yes, because 147,016 is even.

– 10: No, since 147,016 does not end in 0 (it must be even and also end with 0).

– 4: Yes, since 147,016 is divisible by 4 (last two digits 16 is divisible by 4).

– 8: Yes, since 147,016 is divisible by 8 (you can check 147,016 ÷ 8 = 18,377).

The possible numbers of aisles that could be there are: 2, 4, and 8.

Make sure to check if more factors exist based on this reasoning or through extended calculation!