(2x² – 1)(4x² + 7) =
A) 8x^4 + 14x^2 – 4x² – 7
B) 8x^4 + 12x^2 – 7
C) 8x^4 + 28x² – 7
D) 8x^4 + 28x² + 7
(2x² – 1)(4x² + 7) =
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(2x² – 1)(4x² + 7) =
A) 8x^4 + 14x^2 – 4x² – 7
B) 8x^4 + 12x^2 – 7
C) 8x^4 + 28x² – 7
D) 8x^4 + 28x² + 7
To solve the expression ((2x² – 1)(4x² + 7)), we will use the distributive property (also known as the FOIL method when dealing with binomials).
1. Multiply (2x²) by each term in the second polynomial:
– (2x² times 4x² = 8x^4)
– (2x² times 7 = 14x²)
2. Then, multiply (-1) by each term in the second polynomial:
– (-1 times 4x² = -4x²)
– (-1 times 7 = -7)
3. Now, combine all the results:
– (8x^4 + 14x² – 4x² – 7)
4. Combine like terms:
– (8x^4 + (14x² – 4x²) – 7 = 8x^4 + 10x² – 7)
The expression simplifies to (8x^4 + 10x² – 7), which unfortunately does not match any of the options provided A, B, C, or D directly.
However, I encourage you to double-check if there are any typos or alternative forms in the options listed. If you are looking for further assistance with similar expressions, feel free to check the extended services