When iron rusts, solid iron reacts with gaseous oxygen to form solid iron(III) oxide.

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When iron rusts, solid iron reacts with gaseous oxygen to form solid iron (III) oxide. Write the balanced chemical equation for this reaction.

Answer: 4 Fe_(s) + 3 O_2(g) → 2 Fe₂O_3(aq)

Explanation

Write the unbalanced equation with the correct formulas and states.

Unbalanced Reaction: Fe_(s) + O_2(g) → Fe₂O_3(aq)

Use the following steps to balance the equation:

1. Balance O with coefficients of 3 for O₂ and 2 for Fe₂O_3.
2. Balance Fe with a coefficient of 4 for Fe.
3. 4 Fe_(s) + 3 O_2(g) → 2 Fe₂O_3(aq)

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