When iron rusts, solid iron reacts with gaseous oxygen to form solid iron(III) oxide.

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When iron rusts, solid iron reacts with gaseous oxygen to form solid iron (III) oxide. Write the balanced chemical equation for this reaction.

Answer: 4 Fe(s) + 3 O2(g) → 2 Fe2O3(aq)


Write the unbalanced equation with the correct formulas and states.

Unbalanced Reaction: Fe(s) + O2(g) → Fe2O3(aq)

Use the following steps to balance the equation:

  1. Balance O with coefficients of 3 for O2 and 2 for Fe2O3.
  2. Balance Fe with a coefficient of 4 for Fe.
  3. 4 Fe(s) + 3 O2(g) → 2 Fe2O3(aq)

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