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A rock is tossed straight up with a speed of 20 m/s. When it returns, it falls into a hole 10 m deep. a. What is the rock’s velocity as it hits the bottom of the hole? b. How long is the rock in the air, from the instant it is released until it hits the bottom of the hole?
Answer:
A) 24.4 m/s
B) 4.53 s.
Explanation
We will take the ground level is our origin and the upward is the positive direction.
The givens are:
yi = 0
yf = -10m
vi = 20 m/s
To find the final velocity we shall use this kinematic equation
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