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Find a vector function that represents the curve of intersection of the two surfaces. The cylinder x^2+y^2=4 and the surface z=xy
Answer: r(t) = 2 sin t, 2 cos t, 2 sin 2t.
Rationalization. We know that one way of the parametrization of a circle of radius r in R^2 centered at the origin O (0,0) on the xy-plane is:
x = r sin t y = r cos t
We can use these values to substitute to the plane z = xy since the circle and the plane are interesting.
There are many possible answers to this. Another way of parameterizing a circle is by letting x = r cos t and x = r sin t (which is the opposite way but will yield the same z).